The New York Jets have the second best completion percentage in the NFL through five weeks. That’s a shocking thing to say for many reasons, including the key fact that 38-year-old Josh McCown has taken every snap at quarterback for the team this season. The Jets are completing 71.6% of their passes, which is truly remarkable for this franchise.
Today I want to compare the 2017 Jets to their predecessors from 45 years earlier. The 1972 Jets were an interesting team. That year produced a low key entry for the best Joe Namath season: he went 7-6 (missing one game due to injury) but led the NFL in passing yards, touchdowns, yards per attempt, Net Yards per Attempt, and Adjusted Net Yards per Attempt. Namath was the best QB in the NFL that year, and was named a first-team All-Pro by the Pro Football Writers, the NEA, and Pro Football Weekly.1 But Namath completed just 50% of his passes that year, and as a team, the Jets completed just 49.6% of their passes.
It’s easy to look at the 2017 Jets with their 71.6% completion rate — a whopping 22 points higher than the ’72 squad — and conclude that, era adjustments aside, the 2017 Jets passing offense is more efficient. To be clear, era adjustments are enormously important when comparing passers across eras. You almost never want to compare players from different eras without making those adjustments. But today is the rare day where that’s not where I want us to focus. Because as discussed yesterday, completion percentage ignores two key elements of a passing game. [click to continue…]
- Namath was a 2nd-team choice by the AP, which went with Earl Morrall, 9-0 QB of the undefeated Dolphins, as their first-team choice. But it’s not controversial to say that Namath was the best QB in the NFL that year, given that he led in ANY/A and won the majority vote for best QB, and also beat out Morrall in the organizations that made All-Conference (Sporting News and UPI) votes rather than All-Pro votes. Of the five organizations that chose between Namath and Morrall, only one went with Morrall. [↩]